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Find the correct trig ratio given for the triangle below: A 5 13 B 12 C sinA = COSA =

User JLott
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For angle A, perpendicular side is BC = 12, hypotenuse side is AC = 13 and base side is AB = 5.

Determine the trigonometric corresponding to angle A.


\begin{gathered} \sin A=(BC)/(AC) \\ =(12)/(13) \end{gathered}
\cos A=(5)/(13)
\tan A=(12)/(5)

For angle C, perpendicular side is AB = 5, base is BC = 12 and hypotenuse is AC =13.

Determine the trigonometric ratio corresponding to angle C.


\begin{gathered} \sin C=(AB)/(AC) \\ =(5)/(13) \end{gathered}
\begin{gathered} \cos C=(BC)/(AC) \\ =(12)/(13) \end{gathered}
\begin{gathered} \tan C=(AB)/(BC) \\ =(5)/(12) \end{gathered}

User Pswaminathan
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