Question

WRITE AN EQUATION IN POINT-SLOPE FORM OF THE LINE WITH SLOPE -6 THAT CONTAINS TJE POINT (-2,4).

Answer 1

The equation of a line in poins slope form is given by:

`y-y_1=m(x-x_1)`

where m is the slope and (x1,y1) is a point on the line. Plugging the values the problem gives we have:

`\begin{gathered} y-4=-6(x-(-2)) \\ y-4=-6(x+2) \end{gathered}`

Therefore, the equation in point slope form is:

`y-4=-6(x+2)`