Question

I need to get the plane to the airport using y=mx+b form.

Answer 1

The middle of the landing track passes through the points (8, -3) and (10, -2).

The slope of a line that passes through points (x1, y1) and (x2, y2) is computed as follows:

`m=(y_2-y_1)/(x_2-x_1)`

Replacing with the points (8, -3) and (10, -2),

`m=(-2-(-3))/(10-8)=(1)/(2)`

The slope-intercept form of a line is:

y = mx + b

where m is the slope and b is the y-intercept. Replacing with m = 1/2 and point (8, -3), we get:

-3 = 1/2(8) + b

-3 = 4 + b

-3 - 4 = b

-7 = b

Then, the equation is:

y = 1/2x - 7