Question

Rewrite the equation by completing the square.x^2 – 14x + 33 = 0(x+ )^2 =

Answer 1

we have

x^2 – 14x + 33 = 0

Complete the square

(x^2-14x+49)-49+33=0

(x-7)^2-16=0

(x-7)^2=16

square root both sides

`\begin{gathered} (x-7)=\pm4 \\ x=\pm4+7 \\ x_1=4+7=11_{} \\ x_2=-4+7=3 \end{gathered}`

the answer is

(x-7)^2=16