Problem B
In b, the triangle is a right triangle so we can use trig functions
We want to find the hypotenuse. We have the adjacent side to the angle
cos theta = adj / hypotenuse
cos 25 = 10/f
f cos 25 = 10
f = 10 / cos 25
f =11.03377
Problem C
In c, we do not have a right triangle, so we have to use the law of sines
sin F sin H
------- = -------
f h
sin 50 sin 60
--------- = -------------
27 h
Using cross products
h sin 50 = 27 sin 60
Divide each side by sin 50
h = 27 sin 60 / sin 50
h = 30.52392