Step-by-step explanation
We are given the function that defines the profit in relation to the price of the item
The first part of the question:
The form that is most useful for finding the price that gives a profit of 0 dollars will be
the standard form because we can easily substitute p =0 and get the profit
So we have the answer to be
![-2p^2+24p-54](https://img.qammunity.org/2023/formulas/mathematics/college/khmpkxyx2d365v4f3pyrjz280uxi2m9170.png)
For the second part of the question
The profit, when the price is 0 will be when p =0
so that
![\begin{gathered} profit=-2(0)^2+24(0)-54=0-54=-54 \\ \\ Since\text{ the unit of the profit is thousand dollar, then the profit will be} \\ -\text{ \$54,000} \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/dz6vgr27h67i0eqcs4agj73kywkrpigx1j.png)
The profit is -$54,000
The third part of the question
The price that gives maximum profit can simply be obtained from the vertex equation
![-2(p-6)^2+18](https://img.qammunity.org/2023/formulas/mathematics/college/ldnet8lsd3njs0ze8g3oapv1i2r1f92fa9.png)
This will be when
![\begin{gathered} p-6=0 \\ p=6 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/ejnjptfnkm8syxw9olylljnpn9ji9rjmim.png)
So the price that gives maximum profit is $6