Question

Consider the following quadratic function. Y=x^2-2x+3Graph this quadratic function by identifying two points on the parabola, other than the vertex and zeros.Your answer must be between -10 and 10.

Answer 1

We can find two points different than the vertex and zero by giving some values to the variable x. For instance, if we choose the value x=1, we have

`y=1^2-2(1)+3`

which gives

`\begin{gathered} y=1-2+3 \\ y=2 \end{gathered}`

so we have obtained the point

`A=(1,2)`

Similarly, we can substitute the value x=2 and get

`\begin{gathered} y=2^2-2(2)+3 \\ \text{then} \\ y=4-4+3 \\ y=3 \end{gathered}`

then, we have obtained the point

`B=(2,3)`

Then, the graph is