Question

For the following sequence, what is the 73rd term (enter the numeric value only): 16, 24, 32, 40, …73rd term:

Answer 1

`592`

Step-by-step explanation

The given sequence is an arithmetic sequence since each successive term differs by a common difference of 8:

`\begin{gathered} d=24-16=8 \\ d=32-24=8 \end{gathered}`

To find the 73rd term of the sequence, we apply the formula for the nth term of an arithmetic sequence:

`a_n=a_1+(n-1)d`

where a1 = first term = 16

d = common difference = 8

Therefore, the 73rd term of the sequence is:

`\begin{gathered} a_(73)=16+(73-1)8 \\ a_(73)=16+(72\cdot8)=16+576 \\ a_(73)=592 \end{gathered}`

That is the answer.