Answer:
4, 6, 8
Explanation:
For many "consecutive integer" problems, it is convenient to let a variable represent their average. Here, we can let x represent the middle integer.
The sum of the first and third is (x -2) +(x +2) = 2x.
Three times the second, less 6 is 3x -6.
These expressions are equal:
3x -6 = 2x
x = 6 . . . . . . . . . . add 6-2x to both sides
The middle integer is 6, so ...
the consecutive even integers are 4, 6, 8.
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Check
The sum of the first and third is 4+8 = 12. 6 less than 3 times the second is 3(6)-6 = 12. The answer checks.