Given:
Mass of baseball, m = 0.450 kg
Force, F = 1700 N
Let's find the acceleration of the baseball.
To find the acceleration, apply the Newton's second law.
![F=m\ast a](https://img.qammunity.org/2023/formulas/physics/college/ax0kwnnrt6sd7972pbgv1vtgfxpeadi3fp.png)
WHere:
F is the force
m is the mass
a is the acceleration.
Since we are to find the acceleration, rewrite the equation for a:
Divide both sides by m
![\begin{gathered} (F)/(m)=(m\ast a)/(m) \\ \\ (F)/(m)=a \\ \\ a=(F)/(m) \end{gathered}](https://img.qammunity.org/2023/formulas/physics/college/gj7dnlxwss4kfj9yswi97cteg325q7n4oy.png)
Thus, we have:
![\begin{gathered} a=(1700)/(0.450) \\ \\ a=3777.77m/s^2 \end{gathered}](https://img.qammunity.org/2023/formulas/physics/college/cj4ifs5iasps1yik4zbjt3jak6glbxajak.png)
Therefore, the acceleration of the baseball is 3777.77 m/s^2
ANSWER:
![\text{ 3777.77 m/s}^2](https://img.qammunity.org/2023/formulas/physics/college/bwpmaq5iebaj3xfaj5fv9eojoe6ab7yvz5.png)