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Note this is a statistics question from algebra 2Let’s say that a piece of dice is rolled seven times use the binomial distribution form to determine the possibility of rolling exactly 5 3’s

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For this problem, we use the following formula for binomial distribution:


P(x=k)=\begin{bmatrix}{n} & {} & {} \\ {k} & {} & {} \\ {} & {} & \end{bmatrix}p^k(1-p)^(n-k)

Where n is the number of times the piece of dice is rolled and p is the probability of getting a specific number k times, substituting n=7, p=1/7, and k=3 we get:


\begin{gathered} P(x=3)=\begin{bmatrix}{7} & {} & {} \\ {3} & {} & {} \\ {} & {} & {}\end{bmatrix}((1)/(7))^3(1-(1)/(7))^(7-3)=(7!)/((7-3)!3!)((1)/(343))((1296)/(2401)) \\ P(x=3)=0.055 \end{gathered}

Answer: The probability is 5.5%

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