Given
Let x: one number
Let y: second number
Procedure
what number is four less than 3 times a second number
x = 3y - 4
three more than twice the first number is decreased by twice a second the result is 11
2x + 3 - 2y = 11
2x - 2y = 11 - 3
2x - 2y = 8
Replace x with (3y-4) from the 1st statement, and solve for y
2(3y - 4) - 2y = 8
6y - 8 - 2y = 8
4y = 8 + 8
4y = 16
y = 16/4
y = 4
Now for x,
x = 3(4) - 4
x = 12 - 4
x = 8
The answer would be x = 8 and y = 4