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How much energy is required to condense 92.2 g of water?

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To answer this question, we have to use the heat of vaporization of water, that tells us the amount of energy required to evaporate or condense 1 g of water.

According to it, you need to remove 2.257kJ to condensate 1 g of water:


92.2g\cdot(-2.257kJ)/(1g)=-208.09kJ

It means that -208.09kJ are required to condensate 92.2grams of water.

The answer is negative because to condensate a substance you have to remove heat, so when we express it we have to write as a negative amount.

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