Question

Three consecutive interger have sum of 54. find the interger

Answer 1

let the three consecutive number is,

a, a+1 and a+2

sum = 54

a + (a+1) + (a+2) = 54

3a + 3 = 54

3a = 54 - 3

a = 51/3

a = 17

so the intergeres are,

a = 17

a+1 = 17 +1 = 18

a + 2 = 17 + 2 = 19

so, the answer is, 17 , 18 and 19.