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write an equation for the line parallel to the given line that contains CC(1,4); y=-3x+8y=(type your answer in slope-intercept form)

User Sareuon
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Answer:

The equation of the line is:


y=-3x+7

Step-by-step explanation:

Given that the line is parallel to the line;


y=-3x+8

And passes through the point;


(1,4)

Since the line is parallel to the given equation, they must have the same slope.

So, the slope of the line is -3;


m=-3

We now need to calculate the y intercept b of the line;

substituting the slope and the given point;


\begin{gathered} y=mx+b \\ 4=-3(1)+b \\ 4=-3+b \\ \text{add 3 to both sides;} \\ 4+3=-3+3+b \\ 7=b \\ b=7 \end{gathered}

Therefore, the equation of the line is;


y=-3x+7
User Qaswed
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