Question

write an equation for the line parallel to the given line that contains CC(1,4); y=-3x+8y=(type your answer in slope-intercept form)

Answer 1

The equation of the line is:

`y=-3x+7`

Step-by-step explanation:

Given that the line is parallel to the line;

`y=-3x+8`

And passes through the point;

`(1,4)`

Since the line is parallel to the given equation, they must have the same slope.

So, the slope of the line is -3;

`m=-3`

We now need to calculate the y intercept b of the line;

substituting the slope and the given point;

`\begin{gathered} y=mx+b \\ 4=-3(1)+b \\ 4=-3+b \\ \text{add 3 to both sides;} \\ 4+3=-3+3+b \\ 7=b \\ b=7 \end{gathered}`

Therefore, the equation of the line is;

`y=-3x+7`