Question

Graph the following line passing through -1 and 4 whose slope is m equals 1/4

Answer 1

The point-slope form of the equation of a line is generally given as;

`y-y_1=m(x-x_1)`

From the question, we're told that the slope, m, is 1/4 and the line passes through -1 and 4, so our x1 = -1 and y1 = 4, let's substitute these values into the above equation to determine the equation of the line;

`\begin{gathered} y-4=(1)/(4)\lbrack x-(-1)\rbrack \\ y-4=(1)/(4)(x+1) \\ 4y-16=x+1 \\ 4y=x+17 \\ y=(1)/(4)x+(17)/(4) \end{gathered}`

So the line will have a y-intercept at 17/4. See below the graph of the line;