193k views
4 votes
Solve using elimination method3x - 8y = 193x + 5y = -46

User Shimon
by
4.8k points

1 Answer

5 votes

The given set of equations are:


\begin{gathered} 3x-8y=19\ldots\ldots\text{.}(1) \\ 3x+5y=-46\ldots\ldots(2) \end{gathered}

Subtract equation 1 from equation 2, we get,


\begin{gathered} 3x-3x+5y+8y=-46-19 \\ 13y=-65 \\ y=-(65)/(13)=-5 \end{gathered}

Now, substitute -5 for y in equation 1, we get,


\begin{gathered} 3x-(8*-5)=19 \\ 3x+40=19 \\ 3x=19-40=-21 \\ x=-(21)/(3)=-7 \end{gathered}

Thus, x = -7 and y = -5

User Cheerless Bog
by
4.1k points