Given:
The number of nails of a given length is normally distributed with a mean length of 5 in.
A standard deviation of 0.03 in.
To find:
The number of nails in a bag of 120 that are less than 4.94 in long.
Step-by-step explanation:
Using the formula,

Then the probability is,

Therefore, the number of nails in a bag of 120 that are less than 4.94 in long is,

So, The number of nails in a bag of 120 that are less than 4.94 in length is about 3 nails.
Final answer:
The number of nails is about 3 nails.