Question

For a given aqueous solution, is [H+]= 1.0 times 10^-9M, what is [OH-]

Answer 1

`[OH^-]\text{ = }1\text{ }*\text{ 10}^(-5)`

Step-by-step explanation:

Here, we want to calculate the concentration of the hydroxide ions

Mathematically:

`[H^+]\text{ \lbrack OH}^-]\text{ = 10}^(-14)`

We now proceed to substitute the value of [H+]

We have that as follows:

`\begin{gathered} 10^(-9)\text{ }*\text{ \lbrack OH}^-]\text{ = 10}^(-14) \\ [OH^-]\text{ = }(10^(-14))/(10^(-9))\text{ = 10}^(-5) \end{gathered}`