Using the trigonometric ratio:
![\cos \Theta=(adjacent)/(hypotenuse)](https://img.qammunity.org/2023/formulas/mathematics/college/nvvzdhfum5gqdbpzm8wp961fwfc2t91yne.png)
fromthe question, theta = 45 adjacent = a and hypotenuse = 4
substitute the values and evaluate
![\cos 45=(a)/(4)](https://img.qammunity.org/2023/formulas/mathematics/college/gdt3d65vn47wwdkkb35fry46n66k1a90i5.png)
cross-multiply
a = 4 cos 45
a = 2.83
a ≈ 2.8 to the nearest tenth
To find b
adjacent = 5 opposite = b and theta =60
Using the trig. ratio
![\tan \Theta=(opposite)/(adjacent)](https://img.qammunity.org/2023/formulas/mathematics/college/t7k5cgt4awdsuf3po3xp09cp9p5j2dl8gi.png)
![\tan 60=(b)/(5)](https://img.qammunity.org/2023/formulas/mathematics/college/fzaazcsz826m3pckqu6pn69t17byhczsdc.png)
cross-multiply
b= 5 tan 60
b=8.66
b≈ 8.7 to the nearest tenth