We can solve the given system of linear equations like this:
1. Solve for x from the first equation
1x + 25y = 149
x + 25y = 149
x + 25y - 25y = 149 - 25y
x = 149 - 25y
2. Replace 149 - 25y for x into the second equation and solve for y.
3(149 - 25y) - 6y = -39
3×149 - 3×25y - 6y = -39
447 - 75y - 6y = -39
447 - 81y = -39
447 - 447 - 81y = -39 - 447
-81y = -486
y = -486/-81
y = 6
Then, y = 6. By replacing 6 for y into x = 149 - 25y, we get:
x = 149 - 25y
x = 149 - 25(6)
x = 149 - 150
x = -1
Then, the solution to the given system of equations is (-1, 6)