Step-by-step explanation:
3072 J were used to heat one sample of aluminum from 14.75 °C to 28.39 °C. We have to find the mass of the aluminum sample.
The equation that is usually used in this type of problems is:
Q = m * C * ΔT
Where Q is the heat gained or released, m is the mass, C iis the specific heat and ΔT is the temperature change.
Q = 3072 J (positive since the aluminum is being heated)
m = ?
C = 0.897 J/(g°C)
ΔT = Tfinal - Tinitial
ΔT = 28.39 °C - 14.75 °C
ΔT = 13.64 °C
Finally we can replace those values in the formula and solve it for the mass to find the answer to our problem.
Q = m * C * ΔT
m = Q /(C * ΔT)
m = 3072 J/(0.897 J/(g°C) * 13.64 °C)
m = 251 g
Answer: the mass of the aluminum sample is 251 g.