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Write the equation in slope-intercept form of a line that has a slope of and passes through the point (-6, 0).

User Xristina
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1 Answer

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26 votes

Answer:

Slope-intercept form: y = mx + b

(m is the slope, b is the y-intercept or the y value when x = 0 --> (0, y) or the point where the line crosses through the y-axis)

You know:

m = \frac{1}{3}31 So substitute/plug it into the equation

y = mx + b

y=\frac{1}{3} x+by=31x+b To find b, plug in the point (-6, 0) into the equation, the isolate/get the variable "b" by itself

Explanation:

0=\frac{1}{3} (-6)+b0=31(−6)+b

0 = -2 + b Add 2 on both sides to get "b" by itself

0 + 2 = -2 + 2 + b

2 = b

y=\frac{1}{3} x+2y=31x+2

User Dmitry J
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