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How many calories are required to raise the temperature of a 35.0 g sample of iron from 25°C to 35°C? Iron has a specific heat of 0.108 cal/g °C.A. 38 calB. 1.1 calC. 3.8 calD. 93 cal

User Novae
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Answer:


A

Step-by-step explanation:

Here, we want to get the number of calories Q of heat needed

Mathematically:


\begin{gathered} Q\text{ = mc}\Delta T \\ \\ m\text{ = mass = 35 g} \\ c\text{ = specific heat capacity = 0.108 cal/g}\degree C \\ \Delta T\text{ = change in temperature = \lparen35-25\rparen}\degree C\text{ = 10 }\degree C \end{gathered}

Substituting the values, we have it that:


Q\text{ = 35 }*0.108\text{ }*10\text{ = 37.8 cal}

User Sandalone
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