Step-by-step explanation
We need to find the zeros of the following function:

First of all it's important to note that all the terms have a power of x i.e. there's no constant term. This means that x=0 is a zero of the function:

So we have our first zero. Then you can notice that x is a common factor to all terms so we can rewrite our function:

So we can write g(x) as a product of two expressions. This means that if one of the expression is 0 for a given x then g(x) is also 0 for that x. Then the zeros of each term are also the zeros of g(x). The left term is just x and its zero is x=0 the one that we already found. Then the remaining zeros of g(x) are the x-values that make the quadratic expression on the left equal to 0:

Remember that for a quadratic equation ax²+bx+c=0 its zeros are given by the following formula:

In this case we have a=-1, b=1 and c=12 so the zeros of the quadratic expression are:

Then we have another two zeros:

Then the three zeros of g(x) are x=0, x=-3 and x=4.
In a graph the zeros are the x-values of the points where the graph intercepts the x-axis so the answer is the function that intercepts the x-axis at -3, 0 and 4.
Answer
Then the answer is option A.