Question

The Gift Basket Store had the following premade gift baskets containing the following combinations in stock.CookiesMugsCandyTotalCoffee851124Tea47819TOTAL12121943Choose 1 basket at random. Find the probability that it contains candy and coffee (to three places after the decimal point).

Answer 1

Choosing 1 basket at random, the probability that it contains candy and coffee is;

`P(C\cap Co)=0.256`

Step-by-step explanation:

Given the table in the attached image.

Choosing 1 basket at random, the probability that it contains candy and coffee would be;

`P(C\cap Co)=\frac{\text{ number of baskets with candy and coffee}}{\text{ total number of baskets}}`

Given;

`\begin{gathered} \text{number of baskets with candy and coffee = }11 \\ \text{total number of baskets = 43} \end{gathered}`

substituting;

`\begin{gathered} P(C\cap Co)=\frac{\text{ number of baskets with candy and coffee}}{\text{ total number of baskets}}=(11)/(43) \\ P(C\cap Co)=0.256 \end{gathered}`

Therefore, Choosing 1 basket at random, the probability that it contains candy and coffee is;

`P(C\cap Co)=0.256`