Question

Find a_10 5, 12, 19, 26, 33...

Answer 1

Given,

The progression is 5, 12, 19, 26, 33...​

The first term of the series is, a = 5.

The common difference of the series is,

d = 12 - 5 = 7

The 10th term of the series is,

`\begin{gathered} a_(10)=a+(10-1)* d \\ =5+9*7 \\ =5+63 \\ =68 \end{gathered}`

Hence, the 10th term of the series is 68.