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Hey guys can anyone help me find the missing side length pls and ty

Hey guys can anyone help me find the missing side length pls and ty-example-1
User Justin Adkins
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2 Answers

16 votes
16 votes
Sense you have your answer already….

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User Ian Warner
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4 votes
4 votes


\bold{\huge{\green{\underline{ Solution}}}}


\bold{\underline{ Given :- }}

  • We have given a right angled triangle whose values are m, n and 2


\bold{\underline{ To \: Find :- }}

  • We have to find the value of m and n


\bold{\underline{ Let's \: Begin :- }}

In the given right angled triangle, we have

  • Perpendicular height = n units
  • Base = 2 units
  • Hypotenuse = m units

Now, By using trigonometric ratios


\bold{\pink{ Sin Φ = }}{\bold{\pink{(Perpendicular )/(Hypotenuse)}}}


\bold{\red{ Cos Φ = }}{\bold{\red{(Base)/(Hypotenuse )}}}


\bold{\blue { tan Φ = }}{\bold{\blue{(Perpendicular )/(Base )}}}

According to the question :-


\bold{ Cos \: 45° = }{\bold{(2)/(m)}}


\bold{ 1/√2= }{\bold{(2)/(m)}}


\bold{\red{ m = 2√2 \: units }}

  • We know that , Sum of Angles of triangle is 180° .

Therefore,

Let the unknown angle be x


\sf{ 45° + x + 90° = 180° }


\sf{ x = 180° - 135 ° }


\sf{ x = 45° }

Now,


\bold{ Cos \: x° = }{\bold{(n)/(2√2)}}


\bold{ Cos \: 45° = }{\bold{(n)/(2√2)}}


\bold{ 1/√2= }{\bold{(n)/(2√2)}}


\bold { n = 2√2/√2 }


\bold{\red{ n = 2\: units }}

Thus, The value of m = 22 and n = 2


\sf{\blue{ Hence, \: option \: D \: is \: Correct }}

User Weekens
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