The exponential decay is given by:
![A=A_0e^(rt)](https://img.qammunity.org/2023/formulas/mathematics/college/2pswcu1abxaffku3e3t1tbea4ylqccz3b0.png)
where A0 is the initial amount of the element and r is the decay rate.
To find the decay rate we use the fact that the half life is 1590 years; this means that it takes 1590 years for the amount of substance to be half the original amount, that is:
![(1)/(2)A_0=A^{}_0e^(1590r)](https://img.qammunity.org/2023/formulas/mathematics/college/pxfy3azp8t1u43r10dagkp7vflurzpci11.png)
Solving for r we have:
![\begin{gathered} (1)/(2)A_0=A^{}_0e^(1590r) \\ (1)/(2)=e^(1590r) \\ \ln (1)/(2)=\ln (e^(1590r)) \\ \ln (1)/(2)=1590r \\ r=(1)/(1590)\ln (1)/(2) \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/fb2ba9docnm9toc70w8svxt0o110kf9lzq.png)
Hence the decay rate is:
![r=(1)/(1590)\ln (1)/(2)](https://img.qammunity.org/2023/formulas/mathematics/college/dkpo8szl6dys014k0cdujjyk3ut2lxsq2v.png)
Now that we have the decay rate we have that the function describing the amount of radium for our example is:
![A=100e^{((1)/(1590)\ln (1)/(2))t}](https://img.qammunity.org/2023/formulas/mathematics/college/lpcc5micw2wac59oqpmfg88ma075pjll7g.png)
To determine how much radium we have after 1000 years we plug t=1000 in the function above:
![\begin{gathered} A=100e^{((1)/(1590)\ln (1)/(2))(1000)} \\ A=64.67 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/pumrj6u4xaqt5ov4ddlukumzt4r31pmfj4.png)
Therefore after 1000 years we have 64.67 mg of radium-226