1 Answer

ZeroOneZeroR · Answer 1 · 2023-12-01T07:49:36+0000

Hello!

Let's solve each function considering x = 3:

A. f(3) = 128

$\begin{gathered} f(x)=2\cdot4^x \\ f(3)=2\cdot4^3 \\ f(3)=2\cdot64^{} \\ f(3)=128 \end{gathered}$

$\begin{gathered} f(x)=4\cdot2^x \\ f(3)=4\cdot2^3 \\ f(3)=4\cdot8 \\ f(3)=32 \end{gathered}$

$\begin{gathered} f(x)=4\cdot x^2 \\ f(3)=4\cdot3^2 \\ f(3)=4\cdot9 \\ f(3)=36 \end{gathered}$

$\begin{gathered} f(x)=2\cdot x^4 \\ f(3)=2\cdot3^4 \\ f(3)=2\cdot81 \\ f(3)=162 \end{gathered}$

Right answer: alternative D.