We are given that 18 is added to a number. If the number is "n", then we can write this mathematically as:
![n+18](https://img.qammunity.org/2023/formulas/mathematics/high-school/3ie5c905oyznc6hxsm4foos50hptf1qv55.png)
We are also given that the result is divided by 6. This is written as:
![(n+18)/(6)](https://img.qammunity.org/2023/formulas/mathematics/high-school/ob8y9qjwvbd1grr88830y8opd03l5vgtjs.png)
Now, we are given that the result is equal to 1/4 of the number plus 1, this is written as:
![(n+18)/(6)=(1)/(4)n+1](https://img.qammunity.org/2023/formulas/mathematics/high-school/buywm2q7fw6abk50x5js7qxddjng1qjw5f.png)
Now, to determine the number we will solve for "n". First, we will distribute the denominator of the fraction on the left:
![(1)/(6)n+(18)/(6)=(1)/(4)n+1](https://img.qammunity.org/2023/formulas/mathematics/high-school/ytd9xf7m3hw7bfi4bfhjflllvp9alka0xy.png)
Now, we subtract n/4 from both sides:
![(1)/(6)n-(1)/(4)n+(18)/(6)=(1)/(4)n-(1)/(4)n+1](https://img.qammunity.org/2023/formulas/mathematics/high-school/a6lc1ba4evoacx03azplpywnz6xemvi8s0.png)
Solving the operations:
![-(1)/(12)n+(18)/(6)=1](https://img.qammunity.org/2023/formulas/mathematics/high-school/scztgu4obx4ib38kg3eff6j05l7whx7pd3.png)
Now, we simplify the fraction on the left side:
![-(1)/(12)n+3=1](https://img.qammunity.org/2023/formulas/mathematics/high-school/wdtbuxq8onm7un6z3aryou547wrruhy80r.png)
Now, we subtract 3 from both sides:
![-(1)/(12)n+3-3=1-3](https://img.qammunity.org/2023/formulas/mathematics/high-school/7yv9qk680jqb6bsbqtnc4c5i0s1a3l8b26.png)
Solving the operations:
![-(1)/(12)n=-2](https://img.qammunity.org/2023/formulas/mathematics/high-school/ueg3u3indembcus84ilkmc1iwm2amt06yl.png)
Now, we multiply both sides by -12:
![\begin{gathered} n=(-2)(-12) \\ n=24 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/high-school/ef03og9kj08pym6ckhi33rqq1d5mf5r7c3.png)
Therefore, the number is 24.