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If k=3, evaluate the following function [7(k+6)]/(k to the second power) +k to the 3 power)
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If k=3, evaluate the following function [7(k+6)]/(k to the second power) +k to the 3 power)

User Araz Babayev
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1 Answer

3 votes

(7(k+6))/(k^2)+k^3

With k = 3


\frac{7(3+6)}{3^2^{}}+3^3=\frac{7\cdot9}{9^{}}+27=(63)/(9)+27=7+27=34

The answer is 34

User Aylin
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