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What would be the pressure of 1.0 g of O2 contained in a 4.00 L container at 293 K? Answer choices 1.) 0.188 atm2.) 0.178 atm3.) 0.156 atm4.) 1.12 atm

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We would apply the ideal gas formula which is expressed as

PV = nRT

P = nRT/V

where

P represents pressure of gas

V represents volume of gas

n represents number of moles

R is the gas constant

T is the temperature

From the information given,

mass of gas, m = 1 g

V = 4 litres

T = 293

We would calculate the number of moles by applying the formula,

n = mass/molar mass

molar mass of O2 = 32

n = 1/32

R = 0.0821 L atm/mol k

By substituting the values into the formula, we have

P = (1/32 x 0.0821 x 293)/4

Pressure = 0.188 atm

User James Andrew
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