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Write the equation of the each line in the given formThe line through (3, 8) and (-3, 4) in slope-intercept formThe line through (-5, 4) with slope 2/3 in point-slope formThe line with y-intercept 2 through the point (4, 1) in slope-intercept form

User EmerG
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Question 1 (The line through (3, 8) and (-3, 4) in slope-intercept form)

In writing an equation in slope-intercept form, it is important to solve first for the slope of the line. The slope of the line m can be solved using the equation


m=(y_2-y_1)/(x_2-x_1)

We have the points (3, 8) and (-3, 4). Substitute the corresponding values on the equation above and solve. We have


m=(4-8)/(-3-3)=(-4)/(-6)=(2)/(3)

The slope-intercept form of the equation is generally written as


y=mx+b

Use one of the points given in the problem and the calculated m. Substitute this on the equation above to solve for b. I will use (3, 8). We have


\begin{gathered} 8=(2)/(3)(3)+b \\ b=8-2 \\ b=6 \end{gathered}

Hence, the equation of the line is


y=(2)/(3)x+6

Question 2 (The line through (-5, 4) with slope 2/3 in point-slope form)

The point-slope form of a line is described as


y-y_1=m(x-x_1)

Given the slope and the point (-5, 4), we just substitute this on the equation above. The point-slope form is written as


\begin{gathered} y-4=(2)/(3)(x-(-5)) \\ y-4=(2)/(3)(x+5) \end{gathered}

Or we can also rewrite this as


y-4=(2)/(3)x+(10)/(3)

Question 3 (The line with y-intercept 2 through the point (4, 1) in slope-intercept form)

In this problem, the y-intercept is given. The y=intercept is represented as b. We also have a point (4, 1). We can solve for the value of the slope of this line using the equation


y=mx+b_{}

Solving for m, we have


\begin{gathered} 1=m(4)+2 \\ 4m=1-2 \\ 4m=-1 \\ m=-(1)/(4) \end{gathered}

Hence, the slope-intercept form of the line is written as


y=-(1)/(4)x+2

User Joel Stevick
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