Answer:
1/5525
Explanation:
In a standard deck of cards, there are a total of 52 cards.
There are 4 cards labeled 9.
Since the draw is without replacement, the total number of cards reduces after each draw. Therefore:
![\begin{gathered} P(\text{picking the first 9)}=(4)/(52) \\ P(\text{picking the second 9)}=(3)/(51) \\ P(\text{picking the third 9)}=(2)/(50) \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/tgmrsakz3m2u7872z8r6yxqvs05twvlmo0.png)
Thus, the probability of drawing three 9s in a row is:
![P(\text{thre}e\text{ 9s)}=(4)/(52)*(3)/(51)*(2)/(50)=(1)/(5525)](https://img.qammunity.org/2023/formulas/mathematics/college/yi0j59up53alvkfl4a6bjx060pu1r5cdcm.png)
The probability is 1/5525.