Question

If ray AC is the angle bisector of ZDAB, and mZDAC = 58°, what is the mZDAB?

Answer 1

For this case we have aan angle < DAB

And we know that the AC ray is a bisector so then we need to satisfy this:

m < DAC + m < CAB= m < DAB

Since AC is a bisector then we need to satisfy that:

m< DAC = m < CAB= 58º

Then the angle is:

m < DAB= 58*2= 116º