The percentage of ( a% ) is to be applied on the principal amount of ( P ):
![P\text{ = \$658.23}](https://img.qammunity.org/2023/formulas/mathematics/high-school/qhmnzf1dixevofvxqqdeh7o6d0yemsmctn.png)
We need to determine what percentage proportion rate ( a% ) will left us with a disposable amount of ( D ):
![D\text{ = \$645.07}](https://img.qammunity.org/2023/formulas/mathematics/high-school/p4d4i3ybcylypf7ayi7yr09vmn8qzpuy9l.png)
The percentage formula applied at principal amount is:
![D\text{ = P }\cdot\text{ }(a)/(100)\text{ }](https://img.qammunity.org/2023/formulas/mathematics/high-school/ysigy1r9zwofbgoc97q76pvx6hmkcpnpdo.png)
We will plug in the values the respective values as follows:
![\begin{gathered} a\text{ = }(100\cdot D)/(P) \\ a\text{ = }(100\cdot645.07)/(658.23)\text{ = }(64507)/(658.23) \\ \textcolor{#FF7968}{a}\text{\textcolor{#FF7968}{ = 98\%}} \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/high-school/igw6bga90il4umjebx40zx14zbavkx80zp.png)
The amount of percentage reduction applied to the principal amount is ( 2% ) and $645.07 is 98% of principal $658.23.
Hence,
![\textcolor{#FF7968}{98}\text{\textcolor{#FF7968}{ percent}}](https://img.qammunity.org/2023/formulas/mathematics/high-school/y2duno0fvpw9yl7bx5wxymwov1uv6gcm75.png)