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When x=2 and y=4, by how much does the value of 4x^2-yexceed the value of 3x^2 – 3y?

1 Answer

5 votes

it exceeds it by 20

Step-by-step explanation:

Given: when x = 2, y = 4

We will substitute for x and y in each of the expressions:

4x² - y = 4(2)² + 4

4x² - y = 16 + 4

4x² - y = 20

3x² - 3y = 3(2)² - 3(4)

3x² - 3y = 12 - 12

3x² - 3y = 0

To determine the amount 4x² - y exceeds 3x²- 3y, we will substract the value of 3x² - 3y from 4x² - y:

Value of 4x² - y - value of 3x² - 3y

= 20 - 0

= 20

Hence, the value of 4x² - y exceeds 3x² - 3y by 20

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