Question

Please help me calculate the moles of an ideal gas that occupies 166 L at 220.8K and 4.88 atm.

Answer 1

We will use the Ideal Gas Law:

`\begin{gathered} PV=nRT \\ P:pressure\text{ }measured\text{ }in\text{ }atm \\ V:volume\text{ }in\text{ }L \\ n:moles\text{ }of\text{ }gas\text{ }present \\ R:gas\text{ }contant\text{ }that\text{ }converts\text{ }to\text{ }0.082Latmmol^(-1)K^(-1) \\ T:temperature\text{ }in\text{ }K \end{gathered}`

We will substitute the given values into the formula to determine the unknown:

`\begin{gathered} n=(PV)/(RT) \\ n=\frac{4.88\text{ }atm*166\text{ }L}{0.082Latmmol^(-1)K^(-1)*220.8K} \\ n=44.74\text{ }moles \end{gathered}`

Moles of the ideal gas is 44.74.