Question

Pleaseeeeee helpppppppp asappppp! thank you!

Answer 1

Explanation:

`f(x) = {2}^(3) + {x}^(2) - 8x - 4`

`{x}^(2) (2x + 1) - 2(2x + 1) = 0`

`(2x + 1)( {x}^(2) - 2)`

`x = ( - 1)/(2) \\ x = √(2)`

hope it's helpful

Answer 2

`2x^3+x^2-8x-4=(2x+1)(x+2)(x-2)`

Explanation:

Let's collect
`x^2` between the first two terms, and -4 between the last two:

`2x^3+x^2-8x-4=x^2(2x+1) -4 (2x+1)`

At this point you should see there is a common factor
`2x+1`between both terms, then let's collect that:

`2x^3+x^2-8x-4=x^2(2x+1) -4 (2x+1) = (2x+1)(x^2-4)`

Final step is recognizing a difference of squares (x and 2) in the second bracket, to end up our work!

`2x^3+x^2-8x-4=x^2(2x+1) -4 (2x+1) = (2x+1)(x^2-4) =(2x+1)(x+2)(x-2)`