Question

A line passes through the point (4,7) and has a slope of -3.Write an equation in slope-intercept form for this line.

Answer 1

y=-3x+19.

Step-by-step explanation:

Given a line with the following properties:

• Point, (x1,y1)=(4,7)

,

• Slope, m= -3

Substitute into the point-slope form of the equation of a line:

`\begin{gathered} y-y_1=m(x-x_1) \\ \implies y-7=-3(x-4) \end{gathered}`

Next, simplify to write it in the slope-intercept form (y=mx+b).

`\begin{gathered} y-7=-3x+12 \\ y-7+7=-3x+12+7 \\ y=-3x+19 \end{gathered}`

The equation in slope-intercept form is y=-3x+19.