Question

From the top pf a vertical cliff 50 m high, the angle of depression of an object is 38ᴼ. how far is the object from the base of the cliff?

Answer 1

`64\:m\:(approximately)`

1) We can sketch a triangle for that problem, angles of depression/elevation are usually found by applying the tangent ratio

`\begin{gathered} \tan(38)=(50)/(x) \\ x\tan(38)_=50 \\ (x\tan(38))/(\tan(38))=(50)/(\tan(38)) \\ x=63.9970\approx64\:m \end{gathered}`

Rounding off to the nearest whole we can tell the answer is:

`64\:m\:(approximately)`