Question

a. Use the quadratic equation to find the zeros of the function.    b. Average the zeros to find the x-coordinate of the vertex of the parabola.

Answer 1

y= x^2 - 13x + 36

Quadratic equation:

`\frac{-b\pm\sqrt[]{b^2-4\cdot a\cdot c}}{2\cdot a}`

Where:

a= 1

b= -13

c = 36

Replacing:

`\frac{-(-13)\pm\sqrt[]{(-13)^2-4\cdot1\cdot36}}{2\cdot1}`