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while on a luge run in the olympics the sled (mass=157 kg) rounds a horizontal curve of raidus 5.8 m with a speed of 18.5 m/s assuming there is no friction what is the normal force exerted by the seat on the rider if he has a mass of 83 kg?

User Jlapoutre
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1 Answer

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The normal force is the centripetal force which is given by:


F=(mv^2)/(r)

plugging the values given we have:


\begin{gathered} F=((157)(18.5)^2)/(5.8) \\ F=9264.35 \end{gathered}

Therefore, the normal force is 9264.35 N

User Liju
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