Question

Put the following equation in slope intercept form Through (-1,-4) slope=1/3

Answer 1

The first step to solve this problem, is to determine the equation in point-slope, form. Which is given in the form below:

`y-y_1=m\cdot(x-x_1)`

Where "m" is the slope and (x1, y1) are the coordinates of the point. We can apply the data for this problem on the equation:

`\begin{gathered} y-(-4)=(1)/(3)(x-(-1)) \\ y+4=(1)/(3)(x+1) \\ \end{gathered}`

Now we need to convert it to the slope-intercept form. To do that, we have to isolate the "y" on the left side of the equation.

`\begin{gathered} y=(1)/(3)x+(1)/(3)-4 \\ y=(1)/(3)x-(11)/(3) \end{gathered}`

The equation in slope intercept form is: y= (1/3)x - 11/3