Question

About how many inches would the diagonal of the top of the table need to be in order for it to be a perfect triangle? Round to the nearest tenth if necessary

Answer 1

Given

The length of the top table is 15 in.

The width of the top table is 7.5in.

Explanation

To determine the diagonal in order to be perfectly rectangle.

Apply the Pythagoras theorem, in the given rectangle.

`Diagonal\text{ }^2=Length^2+width^2`

Substitute the values

`\begin{gathered} \text{Diagonal}^2=15^2+7.5^2 \\ \text{Diagonal}^2=225+56.25 \\ \text{Diagonal}^2=281.25 \end{gathered}`

So, for the diagonal of the top of the table need to be in order for it to be a perfect rectangle , round to the nearest tenth is

`\begin{gathered} \text{Diagonal}=\sqrt[]{281.25} \\ \text{Diagonal}=16.77in \end{gathered}`

Answer

The diagonal of the top of the table need to be in order for it to be a perfect rectangle is 16.8 in.