Question

In ∆JKL, j=21 cm, < J=39° and

Answer 1

The sketch of the diagram is given above

Given: j = 21 cm

and

`\begin{gathered} l\text{ = }(18.5419)/(0.6293) \\ \\ l\text{ = 29.46 cm} \end{gathered}`

To get the area, we can use the relation

`\text{Area = }(1)/(2)\text{ x l x j x sin 23 }`

we have established that l = 29.46cm, j = 21cm

`\text{Area = }(1)/(2)\text{ x 21 x 29.46 x 0.3907}`

Area = 120.86 square centimeter

=> 120.9 square centimeters to the nearest tenth