hello
to find the total numbers that are greater than 28, we'll count the numbers of asterix on numbers greater than 28

2. The Mean, Median, and Range of the data
the range of any data is the difference between the heighest and lowest value

mode
The mode of any data set is the heighest occuring number in a given date set
in this question, the mode would be between 26 and 28 and this data set can be said to bimodal.
Median
Median is the middle number in a given data set that is arranged from the least to the heighest.
in this case, the median can be calculated as
![\begin{gathered} 25,26,26,26,26,27,27,28,28,28,28,29,29,29,30,30,30,31,31,31,33\text{ and 34 } \\ \text{ since the total number of data set is an even number, we need to just find the average of the two middle numbers which are} \\ i\mathrm{}e\text{ the 11th and 12th numbers which are 28 and 29 respectively} \\ \operatorname{median}=(28+29)/(2) \\ \text{median}=(57)/(2) \\ \text{median=28.5} \end{gathered}]()
Mean
The mean of any given data set is the average of the data. This can be calculated by finding the total sum of the data and divide by the total number of addens
![\begin{gathered} \text{mean}=(25+26+26+26+26+27+27+27+28+28+28+28+29+29+29+30+30+30+31+31+31+33+34)/(22) \\ \text{mean}=(603)/(22) \\ \text{mean}=27.41 \end{gathered}]()