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Given g(x) =✓x-4 and h(x)= 2x-8 what are the restrictions on the domain g*hx>or= ___

Given g(x) =✓x-4 and h(x)= 2x-8 what are the restrictions on the domain g*hx>or-example-1
User Dmoench
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1 Answer

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We have the following functions:


\begin{gathered} g(x)=\sqrt[\square]{x-4} \\ h(x)=2x-8 \end{gathered}

Step 1. Calculate the composition of the functions:


g\circ h

which is defined as follows:


g\circ h=g(h(x))

Thus, we need to substitute h(x) into the x in g(x):


g\circ h=\sqrt[]{(2x-8)-4}

Step 2. Simplify the expression:


\begin{gathered} g\circ h=\sqrt[]{2x-8-4} \\ g\circ h=\sqrt[]{2x-12} \end{gathered}

Step 3. Calculate the restrictions on the domain.

The domain of a function are the possible values for the variable x.

In this case, since we have a square root, we can only have possitive values inside of the square root.

Thus, we need 2x-12 to be equal or greater to 0:


2x-12\ge0

Step 4. Solve the inequality for x:


\begin{gathered} 2x-12\ge0 \\ 2x\ge12 \\ x\ge(12)/(2) \\ x\ge6 \end{gathered}

Answer:

x≥6

User Nditah
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