Question

Refer to the accompanying data display that results from a sample of airport data speeds in Mbps. Complete parts (a) through (c) below.Tinterval(13.046,22.15)x= 17.598Sx=16.01712719n=50A. Express the confidence interval in the format that uses the "less than" symbol. Given that the original listed data use one decimal place, round the confidence interval limits accordingly. ___Mbps

Answer 1

Given:

Tinterval

(13.046, 22.15)

x= 17.598

Sx=16.01712719

n=50

a) Lower limit = 13.046

Upper limit = 22.15

Round to two decimals, we have:

`13.05Mbps<\mu<22.15Mbps`

b) The best point estimate of μ is: 17.60 Mbps

The margin of error is given by:

`E=\frac{Upper\text{ limit}-Lower\text{ limit}}{2}=(22.15-13.05)/(2)=(9.1)/(2)=4.55`

So, the margin of error is E = 4.55 Mbps

c) Since the sample size of 50 is larger than that of 30, the distribution of the sample means can be treated as a normal distribution. Therefore, the answer is D.